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Solving quadratic graphs

Suppose we are asked to sketch the graph y = x2 +3x - 8
To do this we would plot a table of values for x and y-coordinates:

x -5 -4 -3-2 -1 0 1 2
y 2-4 -8 -10 -10 -8 -4 2

We would then plot these coordinates using a nice smooth curve. You should get a regular curve, that resembles a smile. If you don't then you have made a mistake with some of your calculations above

The solution to the equation y = x2 + 3x -8 = 0 is where the curve hits/touches the x-axis.
It can be seen from this graph that we have to solutions.
These, approximately, are were x= -4.8 and x = 1.8

We can then use this graph to solve other equations.
Suppose we wanted to solve x 2 + x -8 =0
If we add 2x to both sides of the equation we get
x 2 + 3x - 8 = 2x

The left hand side is our original graph and the right hand side is a new graph.
We therefore plot the graph y = 2x over our original graph y = x2 + 3x - 8.

The solution to the equation y = x2 + x -8 = 0 is where the two lines intersect.
It can be seen from this graph that we have to solutions.
These, approximately, are were x= 2.4 and x=-3.4

We can plot the actual graph y = x2 + x - 8 to confirm this

The solution to the equation y = x2 + x -8 = 0 is where the graph hits the x-axis.
It can be seen from this graph that we have the two solutions from above solutions.
These, approximately, are were x= 2.4 and x=-3.4